Summary: Sorting the last command

From: <Paf7172_at_aol.com>
Date: Wed Feb 20 2002 - 10:37:12 EST
Thanks to everyone.  

Here are some of the responses I got:

Thanks everyone. 

Paul

last | sort -k 1,1  -k 5M,5 -k 6,6 (I used this one, thanks 
epriebe@acus.com)
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The following Perl script should do the job:

#!/usr/bin/perl -w

/\S/ && push @{$users{(split)[0]}}, $_ while (<>);
print @{$users{$_}} for sort { $a cmp $b } keys %users;

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IFS="
"
for i in `last | head -20`
do
  TIME=`echo $i | awk -F' ' '{print $3,$4,$5,$6," 2002"}' | etime -c -i "%a
%b %d %R %Y"`
  echo $TIME $i
done | sort -n
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sort -k 1,1 -k 4,4M -k 5,5n -k 8,8
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sort -k 3M -k 4n -k 5n
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        last > /var/tmp/last.out
        for i in `awk -F: '{print $1}' /etc/passwd`
        do 
           grep "^$i" /var/tmp/last.out
      done
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Received on Wed Feb 20 09:38:21 2002

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